人力資源經理 | 有龍乃大 | 飛起來了 | 還沒死透 | 凶猛小動物區 |
魔術師的秘密 | 元素方程式 | 獸性大發 | 水族館館長 | 機器學習 |
攻略提供者是 Holt#2539
39
39
平均評分: |
4.2 |
評分: |
65 |
你的投票: |
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1 |
任何等級 25+ 小動物
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Script |
2 | 4.2 | 39 | 120
2:00
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17+ | |||
2 |
Mein Dank geht an "Lapz Gamin" Link
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屬性 |
2 | 5.0 | 0 | 111
1:51
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14 | |||
3 | Script |
2 | 5.0 | 4 | 100
1:40
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14 | ||||
4 |
An early non-Beast racial amplified crit on the Vile Deathroach is acceptable.
Lazy should eat the shield on your 脊喉小果姆 then die before doing damage to your 2nd pet. At that point, the fight is won. |
Script |
2 | 5.0 | 1 | 93
1:33
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12-13 | |||
5 | 屬性 RNG |
2 | 0.0 | 0 | 154
2:34
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23 | ||||
6 |
noted my pet's breeds. let me know if other breeds work. its close but sometimes scooter lives longer. tested 3 times.
first one he died with lazy. second one hit on spokes. third he lived till skeeto came in and the nether was simply surviving one round. i think the third was an anomaly, as lazy had crits the other times |
RNG |
2 | 0.0 | 0 | 135
2:15
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16 |
包括步驟
任何等級 25+ 小動物
技能 任何
屬性: 任何
Substitutes:
1 / 11
1 / 11
I use 小蝸牛史庫特 and 紅螺 but any two snails should do the trick! I recommend using Zoom or another snail as the third pet if you have one left.
之前 | 之後 | 獲得經驗值 | |
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1 | ➜ | 3 | 239 |
2 | ➜ | 4 | 254 |
3 | ➜ | 4 | 267 |
4 | ➜ | 5 | 279 |
5 | ➜ | 6 | 289 |
6 | ➜ | 6 | 297 |
7 | ➜ | 7 | 304 |
8 | ➜ | 8 | 309 |
9 | ➜ | 9 | 312 |
10 | ➜ | 10 | 314 |
11 | ➜ | 11 | 314 |
12 | ➜ | 12 | 312 |
13 | ➜ | 13 | 309 |
14 | ➜ | 14 | 304 |
15 | ➜ | 15 | 297 |
16 | ➜ | 16 | 289 |
17 | ➜ | 17 | 279 |
18 | ➜ | 18 | 267 |
19 | ➜ | 19 | 254 |
20 | ➜ | 20 | 239 |
21 | ➜ | 21 | 223 |
22 | ➜ | 22 | 205 |
23 | ➜ | 23 | 185 |
24 | ➜ | 24 | 163 |
狩旅團之帽 |
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小寵物點心 |
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寵物點心 |
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暗月禮帽 |
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寵物對戰獎勵事件 |
= |
將寵物等級提升至25級並最小化經驗損失的方法 |
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獲得 |
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For the best display of your strategy, please follow these guidelines:
For the best display of your strategy, please follow these guidelines:
I will have to politely disagree with that statement about critters...
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發表在 2020-01-07 15:36:55
change(next) [self.dead]
use(Dive:564)
use(Ooze Touch:445) [enemy.aura(Acidic Goo:368).exists]
use(Acidic Goo:369)
use(#1)
use(#2)
use(#3)
Please note that first two pets won't be enough so you would have to use third one, preferably another snail.
2
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發表在 2021-05-24 10:41:54
2
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發表在 2022-11-11 03:51:21
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2
先登入才可以評論Ziri
發表在 2020-09-27 19:10:35
-1
先登入才可以評論ggg 發表在 2020-10-31 18:00:51
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